Физика, Химия и Математика.

[metalhammer]

2+ or 3+ if i'm not mistaken. It might react as 2+ or 3+

ok. how many electrons does F have in its outer shell? two? and still can form ions as 3+?

[марик - камарик]

ok. how many electrons does F have in its outer shell? two? and still can form ions as 3+?

Yes, it's transition metal. They are different from what you've seen before.

[марик - камарик]

ok there are plenty of programmers here. I have to go to class.

[metalhammer]

если это флоатинг поинт то нужны дополнительные условия:
1. signed or not?
2. how many bits is exponent?

1. sign bit(leftmost digit) zero means positive, sign bit one means negative in the notation.
2. 3

[metalhammer]

according to the book the values for the digits are fractions.

:confused:

[марик - камарик]

decode the following bit pattern using the floating point format:

1) 01001010
2) 10101011

1. sign bit(leftmost digit) zero means positive, sign bit one means negative in the notation.
2. 3

3 => bias is 3

) 01001010 <=> 0 100 1010
+ 2 * (2^0 + 2^-1 + 2^-3)= 2+1+2^-2=3.25 kazhetsya

2) 10101011

- 2^-1 * (1 + 2^-1 + 2^-3 +2^-4)=-(1.5+.25+.125)/2=-1.875/2=-.9375 кажется

[Bibob3d]

decode the following bit pattern using the floating point format:

1) 01001010
2) 10101011

1) 3.25
2)-0.84375
Так?

[metalhammer]

3 => bias is 3

) 01001010 <=> 0 100 1010
+ 2 * (2^0 + 2^-1 + 2^-3)= 2+1+2^-2=3.25 kazhetsya

2) 10101011

- 2^-1 * (1 + 2^-1 + 2^-3 +2^-4)=-(1.5+.25+.125)/2=-1.875/2=-.9375 кажется

5/8 and -(11/64) respectively.

[metalhammer]

3 => bias is 3

) 01001010 <=> 0 100 1010
+ 2 * (2^0 + 2^-1 + 2^-3)= 2+1+2^-2=3.25 kazhetsya

2) 10101011

- 2^-1 * (1 + 2^-1 + 2^-3 +2^-4)=-(1.5+.25+.125)/2=-1.875/2=-.9375 кажется

exponent is extracted using 3-bit excess method. i forgot about that.

so here we go:

4-4= 0 therefore mantissa stays the same: .1010 which is 1/2+1/8=5/8 if you count to the right from the decimal point. now it makes all the sense in the world.

[metalhammer]

пипл, ето долшно бытьь епически легко, но мне не удается пересоставить простое уравнение где перваия масс выходит на левую сооторону уравненя. мне нужно увидеть как автор сделал такое:

F=G*m1*m2/d^2

m1= F*d^2/m2*G